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Friday, June 19, 2015

jax test

$E=\frac{-{{\hbar }^{2}}}{2m}{{\nabla }^{2}}\psi $


$P=P\left( \rho,\theta,\varphi \right)$

$\delta x=\frac{\partial x}{\partial {{q}_{1}}}\delta {{q}_{1}}+\frac{\partial x}{{{q}_{2}}}\delta {{q}_{2}}=\cos \theta \delta r-r\sin \theta \delta \theta $

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